python - regex find what's after slash without showing the slash -


i have script split informations in line, i've succeeded split , extract informations need have slash shows :/ i'de what's after here's example: 

import re   data = "12:05:12.121    o:class (sms:/xxx.xxx@xxx.xx) r:voice/1654354 mid:4312"  ms = re.match(r'(\s+).*mid:(\d+)', data) # extract time , mid  k = re.findall(r"/\s+", data ) # extract source , destination  result = { 'time':ms.group(1), 'mid':ms.group(2), "source":k[0],"destination":k[1]}  print result

and here's result {'source': '/xxx.xxx@xxx.xx)', 'destination':'/1654354', 'mid':'4312','time':'12.05.12.121'}

and result want without slash here: 

{'source': 'xxx.xxx@xxx.xx)', 'destination':'1654354', 'mid':'4312','time':'12.05.12.121'}

wrap \s+ in capturing group:

k = re.findall(r"/(\s+)", data)

and here's way of getting info 1 regex:

import re   data = "12:05:12.121      o:class (sms:/xxx.xxx@xxx.xx) r:voice/1654354 mid:4312"  result = re.search(r'''       (?p<time>.*?)       \s+       .*?       \s+       \(           (?p<type>.*?):/(?p<source>.*?)       \)       \s+       .*/(?p<destination>\d+)       \s+       mid:(?p<mid>\d+) ''', data, re.verbose)  print result.groupdict()

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