Subset a large number into smaller series of numbers using python -


i have big number lets of around hundred digits. want subset big number consecutive number of 5 digits , find product of 5 digits. example first 5 digit number 73167. need check product of individual numbers in 73167 , on.

the sample number follows:

73167176531330624919225119674426574742355349194934969835203127745063262395783180169848018694788518438586156078911294949545950173795833195285320880551112540698747158523863050715693290963295227443043557

i have problem subsetting small numbers out of big number.

my basic starting code :

b = 73167176531330624919225119674426574742355349194934969835203127745063262395783180169848018694788518438586156078911294949545950173795833195285320880551112540698747158523863050715693290963295227443043557 jd = str(b) ch in jd:     number = ch     print (number)

any highly appreciated.

edit: believe grouper overkill in solution, @ solution @haidro https://stackoverflow.com/a/16078696/1219006

using grouper recipe itertools

i'm assuming b string begin because crazy waste of memory make number big.

from itertools import izip_longest operator import mul  def grouper(n, iterable, fillvalue=none):     "collect data fixed-length chunks or blocks"     # grouper(3, 'abcdefg', 'x') --> abc def gxx     args = [iter(iterable)] * n     return izip_longest(fillvalue=fillvalue, *args)  g in grouper(5, b, fillvalue=''):     # , work out product of digits     num = ''.join(g)     prod = reduce(mul, map(int, num))

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