routes - How to programatically list the relationship between two instances in an ontology? -


i have ontology made of relationship follows

company1    :hassubsidary sub1    :hasdepartment cars1    :hassubdepartment manufacturing    :isinbuilding  area1    :hasunit precisionmaching    :hasmachine lathemachine1

i have ontology model these individual created , relationships described.

howe can grammatically list relationship path given input parameters company1, lathemachine1 using jena or other api?

you don't namespace ontology, i'm going speculate it's http://example.com/ontologies/test#. given that, have 2 basic choices: use sparql, or use jena rdf api directly.

in first case, query simple:

prefix ex: <http://example.com/ontologies/test#> select distinct ?relationship { ex:company1 ?relationship ex:lathemchine1 }

you can see how run sparql query java code in jena documentation.

in second case, it's pretty straightforward:

model m = ... rdf model ... ; string ns = "http://example.com/ontologies/test#"; resource company1 = m.getresource( ns + "company1" ); resource lathe1 = m.getresource( ns + "lathemachine1" );  set<property> relationships = new hashset<property>(); (stmtiterator = m.liststatements( company1, null, lathe1 ); i.hasnext();) {   statement s = i.next();   relationships.add( s.getpredicate() ); }

update after poster explained question more in comments:

ok, need path between given nodes. if want a path, opposed all paths, can use onttools.findshortestpath():

path p = onttools.findshortestpath( m, company1, lathe1, filter.any() );

if want paths, use code in findshortestpath template simple breadth-first search.


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