mysql - A server error occurred. Please contact the administrator in Django while executing a stored procedure -
hi find code executed below facing error "a server error occurred. please contact administrator in django while executing stored procedure".
def movementsout_form(request): feature_list = request.session['feature_list'] featuresgroups = request.session['featuresgroups'] if request.method == 'post': form = materialissues_newform(request.post) print "name ", request.post['name_of_material'],request.post['inventory'] if form.is_valid(): cursor = connection.cursor() cursor.callproc('smartlogis2.moveout1', (str(request.post['name_of_material']),str(request.post['date_of_issue']),str(request.post['time_of_issue']),int(request.post['gate']), int(request.post['vechile_id']),int(request.post['way_bill_no']),str(request.post['date_of_shipping']),int(request.post['riv_no']),int(request.post['dbr_no']),str(request.post['description']),int(request.post['inventory']),int(request.post['movement_in']),int(request.post['transport']),int(request.post['billing_address']),str(request.post['status']))); cursor.commit() print "cursor value", print "procedure called" return render_to_response('smartlogis/common.html', {"contacts":feature_list, 'len':len(feature_list) - 1, "featuresgroups":featuresgroups}) else: return httpresponse('data wrongly entered') in settings.py #'django.middleware.csrf.csrfviewmiddleware', also commented
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