php - Selecting data from mysql table usinyg sql -


i have web page want user enter data in text fields should check in mysql table if category user entered text show results here php page code:

   <?php    $host  = "surveyipad.db.6420177.hostedresource.com";     $user  = "";     $pass  = "";     $database ="surveyipad";       $linkid = mysql_connect($host, $user, $pass) or die("could not connect host.");     mysql_select_db($database, $linkid) or die("could not find database.");     if (!function_exists('json_encode'))   {    function json_encode($a=false)   {   if (is_null($a)) return 'null';   if ($a === false) return 'false';   if ($a === true) return 'true';   if (is_scalar($a))   {   if (is_float($a))   {     // use "." floats.     return floatval(str_replace(",", ".", strval($a)));   }    if (is_string($a))   {     static $jsonreplaces = array(array("\\", "/", "\n", "\t", "\r", "\b", "\f", '"'), array('\\\\', '\\/', '\\n', '\\t', '\\r', '\\b', '\\f', '\"'));     return '"' . str_replace($jsonreplaces[0], $jsonreplaces[1], $a) . '"';   }   else     return $a;   }    $islist = true;    ($i = 0, reset($a); $i < count($a); $i++, next($a))   {    if (key($a) !== $i)   {     $islist = false;     break;   }   }  $result = array();  if ($islist)  {   foreach ($a $v) $result[] = json_encode($v);   return '[' . join(',', $result) . ']';  }  else  {   foreach ($a $k => $v) $result[] = json_encode($k).':'.json_encode($v);   return '{' . join(',', $result) . '}';  }  }  }      $flu=$_post['searchcode'];    $query =mysql_query("select * catalog_master category_title '%".$flu."%' ");  $rows = array();  while($row = mysql_fetch_assoc($query)) {  $rows[] = $row;  }   echo json_encode($rows);  ?>

html page code

  <html>   <head>api testing</head>   <body>   <form  action="searchcatalog.php" method="post">   <input type="text" value="enter category"/>   <input type="submit" value="enter value"/>   </form>    </body>   </html>

it showing error below

 warning: mysql_fetch_assoc(): supplied argument not valid mysql result resource in /home/content/i/h/u/ihus235/html/cs/pah_brd_v1/productivo/searchcatalog.php on line 63

may problem query necessary view query , mysql error message

please try , post output

$query =mysql_query("select * catalog_master category_title '%".$flu."%' ") or die ("query error ".mysql_error());

Comments

Post a Comment

Popular posts from this blog

Why does Ruby on Rails generate add a blank line to the end of a file? -

running rails generate controller foo home results in: class foocontroller < application controller def home end end (there's nothing on line in actual file, blank line) is there purpose blank line? it's common use newline indicate end of line, last line. many editors (like vi, use) add in newline silently. consensus text files (especially in unix world) should end in newline, , there have been problems historically if wasn't present. why should text files end newline? the tool used count lines in file "wc" counts newlines in file, without trailing newline show 3 instead of 4. it improves readability of templates used in generator. consider: https://github.com/rails/rails/blob/master/railties/lib/rails/generators/rails/controller/templates/controller.rb to remove trailing newline, template have last line of: end<% end -%> instead of: end <% end -%> that seems less readable me. the discussion below refers ...
Read more

node.js - Bad Request - node js ajax post -

i'm using express 3.0 , node v0.11.0. have button submits form , i'm using ajax post data json object node server. client code is: $('#contact').submit(function(e) { console.log('submit called'); var formdata = json.stringify($('form').serializeobject()); console.log(formdata); $.ajax({ url: "http://localhost:3000/savedata/", type: "post", datatype: 'json', data: {objectdata: formdata}, contenttype: "application/json", complete: function() { console.log('process complete'); }, success: function(data) { console.log('process sucess'); }, error: function() { console.log('process error'); }, }); return false; }); then on server: var express = require('express'); var app = express(); app.set('views', __dirname + '/views'); app.set('view engine', 'jade'); app.use(express.bodyparser());...
Read more

uitableview - Create and use custom prototype table cells in xamarin ios using storyboard -

Image
is possible create , use 'custom' prototype table cells in xamarin ios (monotouch) using storyboard? i find stuart lodge explaining method using xib/nibs: http://www.youtube.com/watch?feature=player_embedded&v=vd1p2gz8jfy let's answer question! looking one. :) 1) open storyboard have viewcontroller tableview: add prototype cell (if there no cell added before): customize cell want (in case there custom uiimage , label): remember set height of cell. select whole tableview , properties window select "layout" tab. on top of properties window should see "row height" - put appropriate value: now select prototype cell once again. in properties window type name of class (it create code-behind class it). in case "friendscustomtableviewcell". after provide "identifier" cell. can see "friendcell". last thing set "style" property set custom. "name" field should empty. once click ...
Read more