LLDB Error with Exponents on C++ -


i have updated calculator code, , adding exponent function. however, when try answer equation, error: (lldb) appreciated, first day c++! yep, that's all! here's code!

#include <math.h> #include <iostream> int int1, int2, answer; bool bvalue(true); std::string oper; std::string cont; using namespace std; std::string typeofmath; int a; int b; int answerexponent;   int main(int argc, const char * argv[]){  // taking user input, first number of calculator, operator, , second number. addition, substraction, multiplication, division     cout<<"______________________________________________\n";     cout<<"|welcome expcalc! want   |\n";     cout<<"|exponent math, or basic math(+, -, x, %)    |\n";     cout<<"|type in 'b' basic math, and'e'      |\n";     cout<<"|exponential math! enjoy! (c) john l. carveth|\n";     cout<<"|____________________________________________|\n";     cin>> typeofmath;     if(typeofmath == "basic" ||        typeofmath == "basic" ||        typeofmath == "b" ||        typeofmath =="b")     {         cout << "hello! please type in first integer!\n";         cin>> int1;         cout<<"great! enter operation: ex. *, /, +, -...\n";         cin>> oper;         cout<<"now need last int!\n";         cin>> int2;          if (oper == "+") {             answer = int1 + int2;         }         if (oper == "-") {             answer = int1 - int2;          }if (oper == "*") {             answer = int1 * int2;         }if (oper == "/") {             answer = int1 / int2;         }         cout<<answer << "\n";         cout<<"thanks using expcalc!\n";      }else if(typeofmath == "exp" ||typeofmath == "e" ||typeofmath == "e" ||typeofmath == "exponent"){         cout<<"enter desired base. example: 2^3, 2 base.\n";         cin>> a;         cout<<"now desired exponent/power of base? ex. 2^3 3 exponent!\n";         cin>>b;         answerexponent = (pow(a,b));         cout<< answerexponent;     } else(cout<<"wrong string!"); }

please help! ask lot of questions aswell, please dont mad! on mac, using xcode 4!

add line includes:

#include <string>

with done, able code compile , run correct output 2^3, in both visual studio, , in gcc 4.7.2 using ideone.com (click here see output). however, compiler still emits warning because of conversion double int should attend casting. change this:

answerexponent = (pow(a,b));

to this:

answerexponent = static_cast<int>(pow(a,b));

with said, compiler emitting warning reason, , casting telling compiler "shut , anyway". better approach avoid need cast. instead of doing above change, change line:

int answerexponent;

to this:

double answerexponent;

this makes more sense, because there little point in calling pow doubles arguments if going throw away fractional part of number afterwards.


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