for loop - How to create a correct array with ls? -


i know can use array=( $( ls . ) ) have next problem code:

array=( $( ls ./cos/cos*.txt ) ) ((  = 0 ;  <= ${#array[*]}-1;  i++  ))     sed 's/$'"/`echo \\\r`/" ${array[$i]} > ./cos/temp.txt     mv ./cos/temp.txt ${array[$i]} done

i have more loops in whole script differents directories respective instructions of sed , mv no problems, have problem part of code, appears command ls saving entire result in first possition of array, i.e. if cos directory has cos1.txt, cos2.txt , cos3.txt, instead of saving cos1.txt in ${array[0]}, cos2.txt in ${array[1]} , cos3.txt in ${array[2]} saving:

cos1.txt cos2.txt cos3.txt in ${array[0]}, entire list in possition 0 of array. know wrong?

it's not clear actual problem is, should write code this:

# don't use ls. let glob expand list of files array=( ./cos/cos*.txt ) # don't iterate on array indices; iterate on items fname in "${array[@]}"; do     # trying add carriage return end of each line?     sed "s/\$/$'\r'/" "$fname" > ./cos/temp.txt     mv ./cos/temp.txt "$fname" done

you don't need array; can put glob in loop:

for fname in ./cos/cos*.txt;    ... done

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