(VBA) Excel : action if content in two columns is matching -


a picture worth thousand words make clear, here picture illustrate situation: enter image description here

so have in column c contents (string , integer) c2 c16. have column g city names (string) g21 g25.

here try : want method probacity() matches between these 2 columns. if there match, want display value (10 example) in corresponding row of g column (in array "probablity of being city"), if no match, it's gonna 0.

so, here in cell g13 should write 10 there match "quezon" , 0 in other cells of array.

here code : 

sub probacity() dim count integer, myresult boolean  count = 2 lastrow range("c" & count).activate myresult = isnumeric(application.match(activecell.value, range("g21:g25"), 0))  if myresult = true range("g" & activecell.row).value = range("g" & activecell.row).value + 0 else range("g" & activecell.row).value = range("g" & activecell.row).value + 10 end if  next count end sub

the problem code myresult returned value false (so set 0 in array).

thanks lot help.

edit: after trying suggestion :
1/ using vba (working "quezon") enter image description here 2/ using formulas... same issue. enter image description here

i want method probacity() matches between these 2 columns. if there match, want display value (10 example) in corresponding row of g column (in array "probablity of being city"), if no match, it's gonna 0.

no need use vba this.

see example

use array formula. have press ctrl+shift+enter after entering formula

=if(count(find($c$9:$c$11,a1)),"10","")

screenshot

enter image description here

edit: since want vba method, try this.

vba method (this work sample data per original post)

sub sample()     dim ws worksheet     dim lookuprange range     dim lrow long      '~~> change relevant sheet     set ws = thisworkbook.sheets("sheet1")      ws         '~~> city list         set lookuprange = .range("g21:g25")          lrow = .range("c" & .rows.count).end(xlup).row          = 2 lrow             .range("g" & i).value = application.evaluate("=if(count(find(" & _                                     lookuprange.address & _                                     "," & .range("c" & i).address & ")),""10"",""0"")")         next     end end sub

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