In MySQL, how to generate percentage by DATE with compound group by? -


i have set of 3 queries return exact data like:

set @mydate = '2013-04-15';  set @dailycpu = (select sum(cputime) eojeot date(stoptime) = @mydate);  select usercode, date(stoptime) thedate,     sum(cputime) 'total cpu secs',     sum(elapsedtime) 'total elapsed secs',     (sum(cputime)/@dailycpu) * 100 pctcpu eojeot date(stoptime) = @mydate group usercode;

this returns (i obfuscated real users)

usercode    thedate     total cpu secs  pctcpu fred        2013-04-15  35873067        0.4069 wilma       2013-04-15  26122714        0.2963 barney      2013-04-15  234689          0.0027 dino        2013-04-15  3284851116      37.2593 pebbles     2013-04-15  48108320        0.5457 bambam      2013-04-15  23671548        0.2685 kazoo       2013-04-15  284847          0.0032

i trying put single query can add group of mydate.

basically, want sum cputime day particular user , show percentage of total cpu time day.

a snippet of table like:

usercode varchar(17) cputime bigint(20) stoptime datetime

i have looked @ self joins trying join sum(cputime) a.date = b.date, did not work.

i thought self join posts read on se cannot find case factors in compound group (usercode, date(stop time) ).


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