Python permutation as list comprehension -


i've got list of strings , permutation. i'm trying apply permutation list, i'm trying keep code clean , concise. @ moment have working solution, , looks this:

mylist = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i'] permutation = [5,2,6,3,7,9,1,4,8]  mynewlist = ['']*9 in range(9):     mynewlist[permutation[i]-1] = mylist[i]  print mynewlist

what don't have initialize list empty list first, , loop through in odd manner. wondering if come cleaner way write this, perhaps using list comprehension? or applying map?

for reference purposes - result of above is:

['g', 'b', 'd', 'h', 'a', 'c', 'e', 'i', 'f']

your algorithm, cleaner:

mynewlist = mylist[:] pos, elem in zip(permutation, mylist):     mynewlist[pos - 1] = elem

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