how to detect if div is hidden by javascript -


i have div, hidden, , in case don't want google adds appear/are loaded @ inside div.

what best practice make such check javascript?

you should @ computed style of node want, via window.getcomputedstyle, rather style attribute of node, css elsewhere may effecting too.

checking whether node covered node more difficult, 1 way use document.elementfrompoint find out node top-most @ specific point, node should until you're satisfied it's visible. example, check centre of node node.

function ishidden(node, checkifcovered) {     var absposition = function absposition(node) {             var x = 0, y = 0,                 h = node.offsetheight || 0, w = node.offsetwidth || 0;             {                 node.offsetleft && (x = x + node.offsetleft);                 node.offsettop && (y = y + node.offsettop);             } while (node = node.offsetparent);             return {x: x, y: y, h: h, w: w};         },         o, style;     if (checkifcovered && document.elementfrompoint) { // if supported         o = absposition(node); // position & size         o.centre = {x: o.x + o.w / 2, y: o.y + o.h / 2}; // centre of node         if (document.elementfrompoint(o.centre.x, o.centre.y) !== node) {             return true; // node in centre => covered         }     }     { // loop on parent nodes         if (node.nodetype === 9) break; // skip #document         style = window.getcomputedstyle(node);         if (   style.display === 'none'             || style.visibility === 'hidden'             || style.opacity === '0'         ) {             return true;         }     } while (node = node.parentnode);     // passed tests, not hidden     return false; }

example usage

ishidden(document.getelementbyid('mydivid')); // true->hidden ishidden(document.getelementbyid('mydivid'), true); // true->hidden or covered

further things consider


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