c++ - Addition on array of char -


this stupid question. playing c++ , find line of code makes me little confused

char buffer[7] = {'0', '1', '0', '9', '0', '1'};  // prints 010901 printf("%s", buffer);  // prints 0901 printf("%s", buffer+2);

why can (+ 2) buffer variable , it's shifted 2 character right?

in context such one, array name buffer "degrades" being pointer first value. since c , c++ support pointer arithmetic, , strings represented pointers arrays of characters, it's fine.

note terminating '\0' character, implied since specify larger size provide initialization data for.

still, code can simplified to:

const char buffer[] = "010901";

you can visualize so:

               +-----+-----+-----+-----+-----+-----+-----+ buffer ------> | '0' | '1' | '0' | '9' | '0' | '1' | '\0 |                +-----+-----+-----+-----+-----+-----+-----+                               ^                               |                               |                          buffer + 2

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