PHP - Syntax [array / variable] -


i want use stripos() filter variable $background , if characters found return keys value $background ;

if(stripos($background, $color) !== false) { $background = value of keys in $color } else { $background = 'no color found'};

$color = array (          'r' => "red",          'y' => "yellow",          '$bgcolor' => array (                        '#ffffd0' => "yellow",                        '#ddffdd' => "green", ));

the variable $bgcolor defined , returns hexadecimal color code. above syntax correct ?

use double quotes variable key. strings single quotes ignoring variables.

<?php header('content-type: text/plain;');  $x = 'check';  $str = "$x";  echo $str, php_eol;  $str = '$x';  echo $str, php_eol; ?>

shows:

check $x

for rest part of code you`ve provided, guess want this:

<?php //header('content-type: text/plain;');  $background = '#ffffd0';  $color = array (         'r' => "red",         'y' => "yellow",         '#ffffd0' => "yellow",         '#ddffdd' => "green"     );  $result = array_key_exists($background, $color) ? $color[$background] : 'not set' ;  echo $result; ?>

shows:

yellow

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