C++ reading string from memory -

i wrote dll application hooked process. works shows first letter.
wanted whole string. string vary 2 letters 32 letters.

//reading memory handle exebaseaddress = getmodulehandlea(0);  char unameaddr = *(char*)((char*)exebaseaddress + 0x34f01c); printf("%c \n", unameaddr); 

i wanted understand parts:

 *(char*)((char*) //<-- for. 

and if possible use if using multilevel pointers:

char multipoint = *(char*)((char*)exebaseaddress + 0x34f01c + 0x123 + 0x321 + 0x20); 

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update

i guess wrong here:

if(unameaddr == "omnicient")     cout << "you omni" << endl; 

i used username name omnicient did not cout you omni. guess compare wrong?

%c displays chars (single characters), %s displays null-terminated char*s (strings):

handle exebaseaddress = getmodulehandlea(0);  char *unameaddr = (char*) exebaseaddress + 0x34f01c; printf("%s \n", unameaddr); 

notice tidied pointer casting, important thing got rid of final dereference (* @ front) , assigned char* (pointer) instead of char.

if string isn't null-terminated (unlikely), need use %.*s , pass length of string too.

as second part of question:

*(char*)((char*) exebaseaddress + 0x34f01c) 

let's break down. inside brackets (therefore first thing evaluated) this:

(char *) exebaseaddress + 0x34f01c 

well that's c cast (casting handle char*) followed addition. in other words, says "treat thing if pointer memory, ahead 0x34f01c bytes of memory" (char 1 byte). pointer new position in memory.

then out of brackets , cast char* again... needlessly. have been:

*((char*) exebaseaddress + 0x34f01c) 

and dereference (the * @ front), says "now tell me bit of memory you're pointing is". in case don't want that, because want whole string, not first letter (inside printf, loops along memory send printing each character until finds 0, aka \0 aka null).