python - breaking while loop with function? -


i trying make function has if/elif statement in it, , want if break while loop.. function text adventure game, , yes/no question. here have come far..

def yn(x, f, g):     if (x) == 'y':          print (f)          break     elif (x) == 'n'          print (g)  name = raw_input('what name, adventurer? ') print 'nice meet you, '+name+'. ready adventure?'  while true:     ready = raw_input('y/n ')     yn(ready, 'good, let\'s start our adventure!',         'that real shame.. maybe next time')

now i'm not sure if using function right, when try out, says can't have break in function. if me problem, , if me if function , calling function formatted wrong, appreciated.

you can work exception:

class adventuredone(exception): pass  def yn(x, f, g):     if x == 'y':          print(f)     elif x == 'n':          print(g)          raise adventuredone  name = raw_input('what name, adventurer? ') print 'nice meet you, '+name+'. ready adventure?'  try:     while true:         ready = raw_input('y/n ')         yn(ready, "good, let's start our adventure!",            'that real shame.. maybe next time') except adventuredone:     pass     # or print "goodbye." if want

this loops while loop on , over, inside yn() function exception raised breaks loop. in order not print traceback, exception must caught , processed.


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