Python recursion, how come my function doesn't work? -


i trying write python 3 recursive function tell me if integer in nested list. not sure how can make code return true if finds in list, , false if doesn't find in list. when print result of loop, bunch of 

false false false false true false false false

etc. but, returns false because last call false, though want return true. how can fix this?

here code:

def nestedlistcontains(nl, target):         if( isinstance(nl, int) ):         return nl          in range(0, len(nl)):        return ( nestedlistcontains(nl[i], target) == target )      return false

and here how i'm calling it

print(nestedlistcontains([[3], [4,5,7], [[[8]]]], 8))

edit: seems working me, seems rather ghetto:

def nestedlistcontains(nl, target):         if( isinstance(nl, int) ):         if( nl == target ):             return 1         return 0      x = 0      n in nl:         x += nestedlistcontains(n, target) == 1              return x != 0

you return result regardless of whether it's true or not. this:

def nestedlistcontains(nl, target):         if isinstance(nl, int):         return nl == target      n in nl:        result = nestedlistcontains(n, target)         if result:            return result      return false

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