c - What is wrong with the fourth character of int variable? -


my machine 32-bit pc running centos system,and used gcc compile c codes. , int variable occupy 4 bytes.so wrote codes this...

    #include "stdio.h"     int main(){            int a=1;            printf("%c",*(&a+1)+65);            printf("%c",*(&a+2)+65);            printf("%c",*(&a+3)+65);     }

i thinking this: pc in 32-bit variable shoule stored in memory this:

   &a    00000001    &a+1  00000000    &a+2  00000000    &a+3  00000000

so think answer should :aaa
real got :qa(the last 1 didn't print out.)
feel puzzled result. , what's more ,if digestion last 2 printf.which is:

    #include "stdio.h"     int main(){            int a=1;            printf("%c",*(&a+1)+65);     }

then got want:a
wrong codes or what;s real wrong thinking variable storing in memory...please me out of stuff,thanks.

here, &a of type int*, &a+1 points next int (4 bytes after). need convert &a char* before : ((char *) &a) + 1


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