Laravel: Use complex condition in JOIN with Fluent -


for reasons of complex schema & library requires either fluent or eloquent used (not raw db::query() ), need create:

left join `camp_to_cabin`  on `camper_to_cabin`.`cabin_id` = `camp_to_cabin`.`cabin_id` , `camp_to_cabin`.`camp_id` =1 or `camp_to_cabin`.`camp_id` null

as join clause; i've tried callbacks & else can think of, cannot proper syntax generate.

i have tried:

    ->left_join('camp_to_cabin', function ($join){         $join->on( 'camper_to_cabin.cabin_id', '=', 'camp_to_cabin.cabin_id')         $join->on( 'camp_to_cabin.camp_id', '=', 1)         $join->on( 'camp_to_cabin.camp_id', '=', null)      })

but puts backticks around 1 & null (i know null bit isn't right - experimenting) can't rid of; otherwise looks pretty close

any help?

tia

thanks, phil - final answer is:

->left_join('camp_to_cabin', function ($join) use ($id){ $join->on( 'camper_to_cabin.cabin_id', '=', 'camp_to_cabin.cabin_id'); $join->on( 'camper_to_cabin.cabin_id', '=', db::raw($id)); $join->or_on( 'camper_to_cabin.cabin_id', 'is', db::raw('null'));  })

looks need use db::raw() otherwise ->on() expects 2 columns. like...

->left_join('camp_to_cabin', function ($join){     $join->on( 'camper_to_cabin.cabin_id', '=', 'camp_to_cabin.cabin_id')     $join->on( 'camp_to_cabin.camp_id', '=', db::raw(1))     $join->or_on( 'camp_to_cabin.camp_id', '=', db::raw(null)) })

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