c++ - How to divide integer by a constant integer with right shift operators? -


this question has answer here:

i'm interested how this, because found out can integer multiplication easily, using left shift operators:

x * 25 = (x << 4) + (x << 3) + x

where sum of base 2 powers equals 25: 2^4+2^3+2^0 = 25

how x / 25 work out right shifts?

edit: i'm not going replace division , multiplication in programs these shift operators in hope of speed boost ;)


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